What is the volume of 0.150 M sodium hydroxide, required to react completely with 250.0 mL of 0.545 M acetic acid, CH3COOH solution?

68.81ml

Explanation:

Using the formula:

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Cb = concentration of base (M)

Va = volume of acid (ml)

Vb = volume of base (ml)

Based on the information given in this question;

Ca = 0.545M

Cb = 0.150M

Va = 250ml

Vb = ?

Using CaVa = CbVb

0.545/250 = 0.150/Vb

Cross multiply

250 × 0.150 = 0.545Vb

37.5 = 0.545Vb

Vb = 37.5/0.545

Vb = 68.81ml

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