2. What volume of a 1.60 mol/L stock solution of calcium chloride would you use to make a 530 mL of a 0.34 mol/L solution? (2 marks)

112.625 mL

Explanation:

Applying,

ML = M'L' Equation 1

Where M = Initial molarity or concentration of calcium chloride, L = initial volume of calcium chloride, M' = Final molarity of calcuim chloride, L' = Final volume of calcuim chloride.

make L the subeject of the equation

L = M'L'/M Equation 2

From the question,

Given: M = 1.60 mol/L, M' = 0.34 mol/L, L' = 530 mL

Substitute these values into equation 2

L = (0.34×530)/1.60

L = 112.625 mL

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)