If 25.00 mL of 0.30 M NaOH is titrated with 0.30 M HCl, what is the pH of the solution after the addition of 25.00 mL of HCl? a.13.00

b.9.00

c.7.00

d.5.00

e.1.00

(Need Work and Explanation)

c. 7.00

Explanation:

The neutralization reaction between NaOH and HCl is the following:

NaOH + HCl → NaCl + H₂O

NaOH dissociates into OH⁻ ions and HCl dissociates into H⁺ ions. At the equivalence point, the total number of moles of OH⁻ is neutralized with the moles of H⁺ added:

OH ⁻ + H⁺ ⇄ H₂O

Moles of NaOH = M x V = 0.025 L x 0.30 mol/L = 7.5 x 10⁻³ mol OH⁻

Since NaOH is a strong base, the moles of NaOH is equal to the moles of OH⁻.

Moles of HCl = M x V = 0.025 L x 0.30 mol/L = 7.5 x 10⁻³ mol H⁺

As we can see, the moles of HCl added are equal to the moles of H⁺ because HCl is a strong acid.

At the equivalence point: 7.5 x 10⁻³ mol OH⁻ =  7.5 x 10⁻³ mol H⁺ (the total amount of OH⁻ reacted with H⁺)

Thus, in the medium we have only the H⁺ from the water equilibrium:

Kw = [H⁺] [OH⁻] = 1 x 10⁻¹⁴

[H⁺] = 1 x 10⁻⁷

⇒ pH = -log [H⁺] = -log (1 x 10⁻⁷) = 7

Therefore, the correct answer is c. 7.00

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

increased stability in the completion of fluorine's outer shell.