Chemistry, 26.05.2021 01:00 emilystartk
) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g) A 1.00-L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is .
Answers: 3
for this reaction is 1.578.
= 0.4 mol
![[NO_{2}]](/tpl/images/1347/8951/53e25.png)
is calculated as follows.
![K_{eq} = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]}\\= \frac{(0.789)^{2}}{(0.3945)}\\= 1.578](/tpl/images/1347/8951/12c3a.png)
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) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g...
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