The half- life of actinium-228 is 6.13 hours What amount of a 70 milliqram sample remains after 24.52 hours?

4.375 milligram

Explanation:

Applying,

A = A'(2ᵃ/ⁿ) Equation 1

Where A = original amount of actinium-228, A' = amount of actinium-228 left after decay, a = Total time, n = half life

make A' the subject of the equation

A' = A/(2ᵃ/ⁿ) Equation 2

From the question,

Given: A = 70 milligram, a = 24.52 hours, n = 6.13 hours

Substitute these values into equation 2

A' = 70/(2²⁴°⁵²/⁶°¹³)

A' = 70/(2⁴)

A' = 70/16

A' = 4.375 milligram

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