A sample of aluminum requires 341 J of energy to raise the temperature from 18.0ºC to 55.0ºC. Calculate the mass of the aluminum sample.

10.22g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat required (J)

m = mass of substance (g)

c = specific heat of substance (J/g°C)

∆T = change in temperature (°C)

According to the information given in this question;

Q = 341J

m = ?

∆T = 55.0ºC - 18.0ºC = 37°C

c of aluminum = 0.902J/g°C

Using Q = m × c × ∆T

341 = m × 0.902 × 37

341 = 33.374m

m = 341 ÷ 33.374

m = 10.22g

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error