The solubility of a gas is 2.0 g/L at 50.0 kPa of pres- sure. How much gas will dissolve in 1 L at a pressure
of 10.0 kPa?
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That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L

Explanation:

Based on Henry's law, the solubility of the gas is directly proportional to the pressure. The equation is:

P1S2 = P2S1

Where P is pressure and S solubility of 1, initial state and 2, final state of the gas.

Replacing:

P1 = 50.0kPa

S1 = 2.0g/L

P2 = 10.0kPa

S2 = ??

50.0kPa*S2 = 10.0kPa*2.0g/L

S2 = 0.4g/L

That means, under 10.0kPa of pressure, 0.4g of gas can be dissolved in 1L

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