How many grams of P2O3 are needed to react with 248 g of NaOH ?

170.43g P2O3

Explanation:

First write and balance the equation:

P2O3 + 4NaOH → 2Na2HPO3 + H2O

NaOH=39.997 g/mol  P2O3= 109.945 g/mol

248g NaOH x 1 mol NaOH/39.997g NaOH x 1 mol P2O3/4 mol NaOH x

109.945g P2O3/ 1 mol P2O3 = 170.43g P2O3

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i'm pretty sure it is letter c.) car