Are manifested as instantaneous charge differences due
to molecular interactions.
Dipole-dipole
interactions
Dispersion
forces
Hydrogen
bonds

dipole: dipole interactions

- dispersion forces (London forces)

- hydrogen bonds

as the attractive forces between molecules becomes larger, it takes more energy to separate them

- as a result, vapor pressures, boiling points and melting points will be larger

occur between molecules that have a permanent dipole moment

- H-ClH-Cl

explanation: well the force of an object when it lands sitting on the ground isthe force of a wide rage of situations crucial to physics? ; ( i 'm trying my best to alot but im not smart enofe you for giving me this chance though! 3(

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: