It took 20.0 mL of NaOH to neutralize 25 mL of 0.50 M HCl. What is the molarity of the base?

5/8 M

Explanation:

NaOH + HCl > NaCl + H2O

in 25 mL of 0.5M acid, we have 1/80 Mol of HCl

it mean we must have 1/80 Mol of NaOH.

20 mL = 1/50 L

(1/80)Mol / (1/50)L = 5/8 M

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