what volume of h2 can be produced at stp from 2 mol cah2 and excess water if the reaction goes 100% to completion?

89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.

Explanation:

The balanced chemical equation of the reaction between calcium hydride, CaH₂ and excess water to produce calcium hydroxide and hydrogen gas is given below:

CaH₂ (s) + 2H₂O (l) > Ca(OH)₂ (aq) + 2H₂ (g)

From the equation of the chemical reaction above, 1 mole of calcium hydride reacts with 2 moles of water to produce 2 moles of hydrogen gas.

Then, 2 moles calcium hydride will react with excess water to produce 2 × 2 -moles of hydrogen gas = 4 moles of hydrogen gas.

One mas a gas at STP has a volume of 22.4 L

4 moles of hydrogen gas will have a volume of 4 × 22.4 L = 89.6 L

Therefore, 89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.

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