Calculate the volume 3.00 moles of a gas will occupy at 24.0°C and 105.2 kPa,
140. L
35.4L
15.4L
70.4L

70.34 litres

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information given in the question;

n = 3 moles

V = ?

P = 105.2 KPa = 105.2/101 = 1.04atm

T = 24.0°C = 24 + 273 = 297K

Using PV = nRT

1.04 × V = 3 × 0.0821 × 297

1.04V = 73.15

V = 73.15 ÷ 1.04

V = 70.34 litres.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6