If 9.2 g of calcium react completely with excess aluminum chloride how many grams of aluminum would be produced? Ca + AlCl3 -> CaCl2 + Al

Explanation:

3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)

According to the question, Ca is the limiting reactant.

Therefore, we equate Ca to Aluminium which is the product whose mass we want to find

Molar mass of Ca- 40g/mol

". ". of Al- 27g/mol

3Ca --> 2Al

3×40 --> 2×27

9.2 --> x

x = 9.2×2×27= 496.8÷120=4.14

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.