subject
Chemistry, 28.05.2021 18:30 Jasten

Please help fast!! ASAP The amount of energy received by a surface depends on the angle of incidence of the incoming light. The angle of
incidence is the angle that a ray of light makes with an imaginary perpendicular line (a normal) extending from the
surface. In this activity, you will answers question based on this and other information
Part A
When we talk about energy from light that a surface receives, we use the word irradiance (E). Irradiance measures the
amount of energy per second (P) that arrives on a surface per unit area (A). As an equation, this idea can be expressed in
this way: E = P/A.
As the angle of the light source moves from 0° to 45°, the illuminated area (A) increases. You can see this increase in the
image. However, although the illuminated area increases, the energy per second (P) from the light is constant. What effect
will an increase in the angle of light, and therefore illuminated area (A), have on irradiance (E)?
angle of incidence


Please help fast!! ASAP

The amount of energy received by a surface depends on the angle of incide

ansver
Answers: 3

Another question on Chemistry

question
Chemistry, 21.06.2019 22:00
Bose-einstein condensation occurs at what temperature?
Answers: 2
question
Chemistry, 22.06.2019 08:00
Joe shines white light into a bowl half full of water at an angle of incident of 27.5°. calculate the angle of refraction in the water given the indices of refraction for air and water are 1.00 and 1.36, respectively.
Answers: 2
question
Chemistry, 22.06.2019 11:00
Ais a mountain created from eruptions of lava, ash, rocks, and hot gases.
Answers: 1
question
Chemistry, 22.06.2019 16:50
Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.
Answers: 1
You know the right answer?
Please help fast!! ASAP The amount of energy received by a surface depends on the angle of incidenc...
Questions
question
English, 11.10.2019 05:00
question
Mathematics, 11.10.2019 05:00
Questions on the website: 13722363