If 1000 molecules enter the first-order reaction and 500 of them disintegrate in 1 s, then how many molecules disintegrate in 2 s?

250 molecules

Explanation:

The number of molecules at the end of 1s are half the initial number of molecules.So, we can see that 1s is basically the half live.

For first order reactions t1/2=(ln2)/k

k=(ln2)/t1/2

k =(ln2)/1s

k =ln 2 /s

Because we know k ,we can use the integrated rate laws.

For 1st order:

ln[A]=ln[A]initial -kt

[A]= ?

[A]initial=1000

k=ln2

t=2s

ln[A]=ln[1000]-[ln 2 x 2]

ln[A]~5.521

[A]=e^(5.521)

    =250 molecules

Hope it helps:)

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.