Sodium chloride is produced from its elements through a synthesis reaction. What mass of each reactant would be required to produce 22.0 mol of sodium chloride? sodium

506.0 g sodium and 778.8 g chlorine gas

Explanation:

The elements from which sodium chloride (NaCl) is composed are sodium (Na) and chlorine (Cl). Thus, the chemical equation for the production of sodium chloride (NaCl) from sodium (Na) and chlorine gas (Cl₂) is the following:

2Na(s) + Cl₂(g) → 2NaCl(s)

According to the balanced equation, 2 moles of NaCl are produced from 2 moles of Na(s) and 1 mol of Cl₂. To produce 22.0 mol of NaCl, we need:

22.0 mol NaCl x 2 mol Na(s)/2 mol NaCl = 22.0 mol Na(s)

22.0 mol NaCl x 1 mol Cl₂/2 mol NaCl = 11.0 mol Cl₂

Now, we convert the moles of each reactant to grams with the molar mass (MM) of the compound:

MM(Na) = 23 g/mol

22.0 mol Na x 23 g/mol = 506.0 g Na(s)

MM(Cl₂) = 35.4 g/mol x 2 = 70.8 g/mol

11.0 mol Cl₂ x 70.8 g/mol = 778.8 g Cl₂

Therefore, it is required a mass of 506.0 grams of Na(s) and a mass of 778.8 grams of Cl₂ to produce 22.0 mol of NaCl.