How many grams of Mg would be needed to react with 6.0 moles HCl?

72g

Explanation:

The balanced equation of the reaction between Magnesium (Mg) and hydrochloric acid (HCl):

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

Based on this equation, 1 mole of Mg needs to react with 2 moles of HCl.

Hence, 6 moles of HCl will need to react with 6 × ½ = 3 moles of Mg.

Using the formula; mole = mass/molar mass

Molar mass of Mg = 24g/mol

3 = mass/24

mass = 72g.

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