When the pressure is 1.22 atm, a sample of hydrogen gas has a volume of 1.88L. What is its volume if the pressure is increased to 1.45 atm?

1.58 L

Explanation:

Use Boyle's law, which is defined as

p1v1 = p2v2

In this case we're solving for V2 because the rest of the variables are given.

p1 = 1.22 atm

v1 = 1.88L

p2 = 1.45 atm

v2 = ?

p1v1 = p2v2

(1.22 atm)(1.88L) = (1.45 atm)(v2)

v2 = (1.22 atm)(1.88L) ÷ (1.45 atm) = 1.58 L

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