If 10.0 grams of sodium phosphate are reacted, what mass of barium nitrate is
required?

The mass of barium nitrate required is 23.91 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

   ......(1)

Given mass of sodium phosphate = 10.0 g

Molar mass of sodium phosphate = 163.94 g/mol

Plugging values in equation 1:

The chemical equation for the reaction of sodium phosphate and barium nitrate follows:

By the stoichiometry of the reaction:

If 2 moles of sodium phosphate reacts with 3 moles of barium nitrate

So, 0.061 moles of sodium phosphate will react with = of barium nitrate

Molar mass of barium nitrate = 261.337 g/mol

Plugging values in equation 1:

Hence, the mass of barium nitrate required is 23.91 g

not clear

the temperature of the gas, in k, not celsius.