How many moles of Chlorine gas are required to produce 5.35 moles of NaCl in this
reaction?

2.675 moles of Chlorine gas are required

Explanation:

Chlorine gas, Cl2, reacts with NaBr to produce NaCl and Br2 as follows:

Cl2 + 2NaBr → 2NaCl + Br2

Where 1 mole of chlorine gas produce 2 moles of NaCl

Thus, to produce 5.35 moles of NaCl are required:

5.35mol NaCl * (1mol Cl2 / 2mol NaCl) =

2.675 moles of Chlorine gas are required

Yes she is correct. the answer is completely correct

Non metal is an element or substance that is not a metal metal is a solid material that is typically hard, shiny, malleable, fusible, and ductile, with good electrical and thermal conductivitymetalloid is an element (e.g., germanium or silicon) whose properties are intermediate between those of metals and solid nonmetals. they are electrical semiconductors.