Organize the following list of elements from highest to lowest Ionization Energy: Phosphorus, Bismuth, Arsenic, Antimony, Nitrogen

The list of elements from highest to lowest Ionization Energy is Nitrogen > Phosphorus > Arsenic > Antimony > Bismuth.

Explanation:

The amount of energy required to remove the most loosely bound electron from an isolated gaseous atom or ion is called ionization energy.

Element with a half-filled orbital requires much more energy to remove an electron. This is because element with a half-filled electronic configuration is the most stable in nature.

More stable or tightly electrons are bound to the nucleus of an atom more will be its ionization energy. This also means that smaller is the atom higher will be its ionization energy.

When we move from top to bottom in a group the size of atom increases and the attraction between nucleus of atom and its valence electrons decreases. Hence, less will be the ionization energy.

Therefore, ionization energy decreases on moving down a group.

So, the given elements Phosphorus, Bismuth, Arsenic, Antimony, Nitrogen are all group 15 elements. Hence, decreasing order of their ionization energy is as follows.

Nitrogen > Phosphorus > Arsenic > Antimony > Bismuth

Thus, we can conclude that the list of elements from highest to lowest Ionization Energy is Nitrogen > Phosphorus > Arsenic > Antimony > Bismuth.

n has four pairs of electrons in the valence shell, electrons repel one another ,n has 7 protons in its nucleus, and since n has 7 protons, it must fill the second shell, giving it 4 pairs of electrons. the electrons form 3 bonds and 1 lone pair of electrons. each pair of electrons repels the other pairs, so they are equally far apart.

so all of the above