If a dose of antacid containing 28 g Al(OH)3 reacts to produce 44 g AlCl3, what is the percentage yield of AlCl3

96%

Explanation:

Step 1: Write the balanced neutralization reaction

Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O

Step 2: Calculate the theoretical yield of AlCl₃

According to the balanced equation, the mass ratio of Al(OH)₃ to AlCl₃ is 81.03:133.34.

28 g Al(OH)₃ × 133.34 g AlCl₃/81.03 g Al(OH)₃ = 46 g AlCl₃

Step 3: Calculate the percent yield of AlCl₃

The real yield of AlCl₃ is 44 g. We can calculate the percent yield using the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 44 g / 46 g × 100% = 96%

the answer for sodium is 0.186

the answer for rubidium is 0.251

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