Solve the given problems showing all work for each. 1. Calculate the molar mass/formula mass of ammonium sulfate -- (NH4)2SO4 , The atomic mass of Nitrogen (N) = 14.0, Sulfur (S) = 32.1, Hydrogen (H) = 1.0, & Oxygen (O) = 16.0 *

The molar mass of ammonium sulfate, (NH₄)₂SO₄ = 132.1 g

Explanation:

The molar mass of a compound is the mass of 1 mole of the given substance.

For a compound the molar mass of the compound is obtained by summing the product of the number of atoms and the atomic masses of the atoms present in the compound.

To calculate the molar mass of ammonium sulfate, (NH₄)₂SO₄:

Atomic masses of the elements are as follows; Nitrogen (N) = 14.0, Sulfur (S) = 32.1, Hydrogen (H) = 1.0, & Oxygen (O) = 16.0

Mass of Nitrogen present = 14.0 × 2 = 28.0 g

Mass of hydrogen present = 1.0 × 4 × 2 = 8.0 g

Mass of sulfur present = 32.1 × 1 = 32.1 g

Mass of oxygen present = 16.0 × 4 = 64.0 g

Molar mass of ammonium sulfate, (NH₄)₂SO₄ = (28.0 + 8.0 + 32.1 + 64.0) g = 132.1 g

Therefore, the molar mass of ammonium sulfate, (NH₄)₂SO₄ = 132.1 g

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

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