Chemistry, 04.06.2021 18:50 lulu5563

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

Answers: 1

Show answers

Answers

Answer from: demigod0701

The question is incomplete, the complete question is:

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:

(a): Calculate the grams of N_2 in 10.58 L of nitrogen gas

(b): Calculate the grams of N_2 in $5.03\times 10^{20}$ moles of nitrogen gas

(c): Calculate the moles of N_2 molecules in 3.94 grams of nitrogen gas

(d): Calculate the moles of N_2 molecules in 4.73 L of nitrogen gas

The correct options are (b) and (c).

Explanation:

We are given:

Molar mass of N_2 = 28.02 g/mol

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

At STP conditions:

1 mole of gas occupies 22.4 L of volume

For the given options:

(a): Volume is given and to calculate the mass of N_2 , we need to use both the conversion factors above.

The equation formed will be:

Mass of N_2 = $\frac{1mol}{22.4L}\times 10.58L\times 28.02 g/mol$

(b): Moles are given and to calculate the mass of N_2 , we need only the first conversion factor.

The equation formed will be:

Mass of N_2 = $(5.03\times 10^{20}mol)\times 28.02g/mol$

(c): Mass is given and to calculate the moles of N_2 molecules, we need only the first conversion factor.

The equation formed will be:

Moles of N_2 molecules = $\frac{3.94 g}{28.02g/mol}$

(d): Volume is given and to calculate the moles of N_2 molecules, we need only the second conversion factor.

The equation formed will be:

Moles of N_2 molecules = $\frac{1mol}{22.4L}\times 4.73L$

Hence, the correct option is (b) and (c)

Answer from: Quest

Distance and velocity graph

Answer from: Quest

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in $h_{2}s$ , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between $h_{2}s$ molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent $h_{2}s$ molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

Another question on Chemistry

Chemistry, 21.06.2019 22:30

Asolution contains 225 g of sodium chloride, nacl, dissolved in enough water to make a 0.25 l of solution. what is the molarity of the solution? a. 3.88 m, b. 1.03 m, c. 1.5 m, d. 15.5 m

Answers: 3

Answer

Chemistry, 22.06.2019 05:20

Identify and describe the three ways that mutations affect organisms.

Answers: 1

Answer

Chemistry, 22.06.2019 15:00

Describe what happens to the molecules as water goes from ice to liquid to vapor. be sure to explain what happens to the temperature during the phase changes.

Answers: 2

Answer

Chemistry, 22.06.2019 15:30

Two metal blocks that have slightly different temperatures are placed next to one another. after five minutes, they both have lower but equal temperatures. according to the law of conservation of energy, what most likelyhappened? energy was created inside the blocks.energy was destroyed inside the blocks.energy was absorbed into the blocks from outside the system.energy was transferred from the warmer block to the cooler block.

Answers: 2

Answer

You know the right answer?

Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more...

Questions

Chemistry, 12.12.2020 16:00

All the following are compounds except. A. water. B. sugar solution. C. aqueous. D. sulphur dioxide...