Calculate the pressure in atm of .68 mol of H at 298K and occupying 4.5 L

3.7 atm

General Formulas and Concepts:

Atomic Structure

Moles

Gas Laws

Ideal Gas Law: PV = nRT

P is pressureV is volumen is number of molesR is gas constantT is temperature

Explanation:

Step 1: Define

Identify variables

[Given] n = 0.68 mol H

[Given] T = 298 K

[Given] V = 4.5 L

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] P

Step 2: Find Pressure

Substitute in variables [Ideal Gas Law]:                                                          P(4.5 L) = (0.68 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)(298 K)Multiply [Cancel out units]:                                                                               P(4.5 L) = (0.055828 L · atm · K⁻¹)(298 K)Multiply [Cancel out units]:                                                                               P(4.5 L) = 16.6367 L · atmIsolate P [Cancel out units]:                                                                             P = 3.69705 atm

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

3.69705 atm ≈ 3.7 atm

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes