2P(s) + X(g) ↔ P2X(g) at 20°C, Keq= 4.0 Initially, 2.0 moles of P(s) and 1.0 mole of X(g) are put into a 1.0L flask and allowed to react until they reach equilibrium. The molarity of P2X (g) present at equilibrium is: a. 1.0 M b. 0.8 M c. 0.4 M d. 0.1 M

b. 0.8 M

Explanation:

Based on the reaction, Keq is defined as:

Keq = 4.0 = [P2X] / [X]

As P is a pure solid, its concentration is not taken into account

The initial concentration of X is 1.0mol/L = 1M, the equilibrium concentrations are:

[X] = 1M - X

[P2X] = X

Where X is the reaction coordinate

Replacing:

4.0 = X / 1-X

4.0 - 4.0X = X

4.0 = 5.0X

0.8M = X = [P2X]

Right answer is:

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

c. electrical charges of ionic bonds.