How many liters of hydrogen (at 0.97atm and 24c) will produce 180 grams of water I also need to know how to get the answer.

H₂ + ½O₂ → H₂O

2g → 18g

So, 18g water needs 2g H₂

So, 1g water needs 2/18g H₂

So, 180g water needs 2/18 x 180g H₂

→ 20 litres of H₂

Explanation:

Molar mass of water, H2O = 2 + 16 = 18

So 180g of water contains 10M

H2 + O -> H2O

10M of Hydrogen is needed to produce 10M of water.

Molar volume at STP = 22.4L

So 10M of Hydrogen at STP = 224L

With Ideal Gas Law, P1V1/T1 = P2V2/T2

At STP, P1 = 1atm, T1=273K

At 0.97atm and 24c (273+24 = 297K), 10M of Hydrogen will take up:

1*224/273 = 0.97*V2/297

V2 = 224*297/273/0.97

= 251.23L

So the answer is 251.23L

the maximum mass of nh3 is nh3 in grams