1. A light bulb is filled with 3.54 g of argon at 25 C and 725 mmHg. What is the volume of this gas?

The volume of given gas is 2.27 L.

Explanation:

Given: Mass = 3.54 g

Temperature = = (25 + 273) K = 298 K

Pressure = 725 mm Hg (1 mm Hg = 0.00131579) = 0.95 atm

As moles is the mass of substance divided by its molar mass.

So, moles of argon (molar mass = 40 g/mol) is as follows.

Formula used to calculate the volume of given gas is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

Thus, we can conclude that the volume of given gas is 2.27 L.

6.4 cm (max) - 25 cm (min)

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