I’m confused on this review question

1.58×10¯⁷ M.

Explanation:

From the question given above, the following data were obtained:

pH = 6.8

Concentration of hydronium ion [H₃O⁺] =?

The pH of a solution is given by the following equation:

pH = –Log [H₃O⁺]

With the above formula, we can obtain the concentration of hydronium ion [H₃O⁺] as follow:

pH = 6.8

Concentration of hydronium ion [H₃O⁺] =?

pH = –Log [H₃O⁺]

6.8 = –Log [H₃O⁺]

Multiply both side by by –1

–6.8 = Log [H₃O⁺]

Take the anti log of –6.8

[H₃O⁺] = antilog (–6.8)

[H₃O⁺] = 1.58×10¯⁷ M

Therefore, the concentration of hydronium ion [H₃O⁺] in the solution is 1.58×10¯⁷ M.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this