For the reaction equilibrium, H2 (9) + 12 (g) --> 2 HI(g)
Kp=54.8 at 698 K.
At a particular equilibrium position, the concentration of H2 and I2 at equilibrium are each 0.020 mol L-1 and that of HI is 0.148 mol L-1, If the concentration of HI is instantaneously increased to 0.53 mol L-1 calculate the concentrations of all the reaction components when the new equilibrium position is established.​

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.