Calculate the pH after 0.020 mol HCl is added to 1.00 L of each of the four solutions below. Answer with the correct number of significant figures. (a) 0.122 M HONH2 (Kb = 1.1 ✕ 10-8)
(b) 0.122 M HONH3Cl
(c) pure H2O
(d) a mixture containing 0.122 M HONH2 and 0.122 M HONH3Cl

it is the most commonly accepted one

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole