How many grams of p2o3 can be produced from 95l o2 at STP

Explanation:

Balanced Equation

P

2

O

3

+

3H

2

O

→

2H

3

PO

3

First use the balanced equation to determine the mole ratio between

H

3

PO

3

and

P

2

O

3

. This ratio will be used to determine the moles

P

2

O

3

required to produce

10.2

moles

H

3

PO

3

.

Mole Ratio Between

P

2

O

3

and

H

3

PO

3

from the balanced equation.

1

mol P

2

O

3

2

mol H

3

PO

3

and

2

mol H

3

PO

3

1

mol P

2

O

3

Multiply the moles

H

3

PO

3

by the molar mass that cancels

H

3

PO

3

and leaves

P

2

O

3

10.2

mol H

3

PO

3

×

1

mol P

2

O

3

2

mol H

3

PO

3

=

5.10 mol P

2

O

3

Now that the moles

P

2

O

3

required to produce

10.2 mol H

3

PO

3

are known, multiply the number of moles by its molar mass,

109.945 g/mol

. https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for

P

2

O

3

to produce

10.2 mol H

3

PO

3

.

5.10

mol P

2

O

3

×

109.945

g P

2

O

3

1

mol P

2

O

3

=

561 g P

2

O

3

rounded to three significant figures

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )