18)How many moles of aluminum are needed to react completely with 3.2 mol of FeO? 2Al(s) + 3FeO(s) → 3Fe(s) + Al2O3(s)
A)3.2 mol
B)2.1 mol
C)1.6 mol
D)6.4 mol
E)4.8 mol

show work

C

Explanation:

How many moles of aluminum are needed to react completely with 3.2 mol of FeO?

C)1.6 mol

answer: h+ its less than oh

explanation:

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o