Use the average acceleration obtained in Activity 1 to determine how far the ball should drop at 0.3 second, 0.5 second, and 0.7 second. Using the simplified formula y = 1/2 at2 (because y0 = 0 and v0 = 0), calculate y to one decimal place.

0.3 sec : -0.4 m

0.5 sec: -1.2 m

0.7 sec: -2.3 m

Explanation:

0.3 sec: 1/2(-9.3 m/s^2)(0.3 s)^2 = -0.4 m

0.5 sec: 1/2(-9.3 m/s^2)(0.5 s)^2 = -1.2 m

0.7 sec: 1/2(-9.3 m/s^2)(0.7 s)^2 = -2.3 m

a non redox reaction occurs when there is not a transfer of electrons. for redox reactions, which are reduction-oxidation reactions, a change in the oxidation number occurs. elements that are reduced gain electrons, and elements that are oxidized lose electrons.

explanation:

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g