How many moles of NaOH are needed to react with 200g of H2SO4
using the equation below?
H2SO4 + 2NaOH -> Na2SO4 + 2H2O

4.08moles

Explanation:

The balanced equation of this reaction is given as:

H2SO4 + 2NaOH -> Na2SO4 + 2H2O

From the above balanced equation, 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

Using the formula below to calculate the number of moles in 200g of H2SO4;

mole = mass/molar mass

Molar mass of H2SO4 = 1(2) + 32 + 16(4)

= 2 + 32 + 64

= 98g/mol

number of moles = 200g ÷ 98g/mol

n = 2.04mol

Since 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

Then, 2.04mol of H2SO4 is needed to react with 2.04 × 2/1 = 4.08moles of NaOH.

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