Question 11 of 16 V Question 11
How many moles of HCI will just react with 0.424 g Ba(OH)2?
2HCI + Ba(OH)2 - BaCl2 + 2H2O
O A) 4.94 x 10 mol
O B) 124 x 10-3 mol
O C) 2.48 x 10 mol
O D) 9.90 x 10 mol

A

Explanation:

How many moles of HCI will just react with 0.424 g Ba(OH)2?

A) 4.94 x 10 mol

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2