A student was given the task of titrating a 20.mL sample of 0.10MHCl(aq) with 0.10MNaOH(aq). The HCl(aq) was placed in an Erlenmeyer flask. An equation for the reaction that occurs during the titration is given above. (a) According to the equation for the reaction, if the amount of the reactants is halved, how does this affect the amount of H2O(l) produced in the reaction

The amount H2O produced is also halved

Explanation:

A strong acid as HCl reacts with a strong base as NaOH producing water and a salt, NaCl. The reaction is:

HCl + NaOH → NaCl + H₂O

Where 1 mole of HCl reacts per mole of NaOH to produce 1 mole of water.

That means, if the amount of HCl and NaOH is halved, the amount H2O produced is also halved because 1 mole of each reactant produce 1 mole of water

i think tornado but not 100%