If an 83.00 g sample of Iron has a starting temperature of 297K and an ending temperature of 329K, how much heat will be lost from the iron sample?

1192.54 J

Explanation:

Applying,

Q = cm(t₂-t₁) Equation 1

Where Q = Amount of heat lost, c = specific heat capacity of the iron, m = mass of the iron, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 83 g = 0.083 kg, t₁ = 297 K, t₂ = 329 K

Constant: c = 449 J/kg.K

Substitute these values into equation 1

Q = 449(0.083)(329-297)

Q = 449(0.083)(32)

Q = 1192.54 J