HELP if 3.50 moles of sodium hydroxide reacts with excess lead(II) nitrate, how many moles of Pb(OH)2 are produced?

1.5 moles of are produced.

Explanation:

We are given:

Moles of sodium hydroxide = 3.50 moles

The given chemical equation follows:

By stoichiometry of the reaction:

If 2 moles of NaOH produces 1 mole of

So, 3 moles of NaOH will produce = of

Hence, 1.5 moles of are produced.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

diaria maybe go see a doctor about that