For the following reaction: 4C2H3Cl + 702 → 8CO + 6H20 + 2Cl2 If the reaction of 57.8 grams of O2 produces 36.5 grams of CO, what is the percent yield?​

Explanation:

Hello there!

In this case, according to the given chemical reaction:

It turns out possible for us to realize about the 7:8 mole ratio of O2 to CO, and therefore, the theoretical yield of the latter is calculated via stoichiometry:

Finally, the percent yield is calculated by dividing the actual yield, 36.5 g by the just computed theoretical one:

Regards!

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