How many moles are in 89 grams of KCI

The number of moles in 89 grams of KCl is approximately 1.193 moles

Explanation:

A mole of an element or compound, is the quantity of the element or compound that contains 6.022 × 10²³ molecules of the element or compound, such that the molar mass of one mole is dependent on the mass of each molecule of the element or compound that make up the 6.022 × 10²³ particles

The given parameters are;

The mass of the KCl = 89 grams

The Molar mass, MW, of potassium, K = 39.1 g/mole

The Molar mass, MW, of chlorine, Cl = 35.5 g/mole

Therefore, given that KCl, has one K and one Cl, per mole, we have;

The Molar mass, MW, of potassium chloride, KCl = (39.1 + 35.5) g/mole = 74.6 g/mole

Therefore, the number of moles of KCl in 89 g, 'n' is given as follows;

n = (89 g)/(74.6 g/mole) ≈ 1.193 moles

The number of moles in 89 grams of KCl, n ≈ 1.193 moles.

mass of KCl = 89 g

MW K = 39.1 g/mol

MW Cl = 35.5 g/mol

moles of KCl

Step 1: Calculate the MW of KCl.

MW KCl = MW K + MW Cl

MW KCl = 39.1 g/mol + 35.5 g/mol

MW KCl = 74.6 g/mol

Step 2: Solve for the number of moles of KCl.

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h let me think

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3