Alkynes do not react directly with aqueous acid as do alkenes, but will do so in the presence of mercury(II) sulfate as a Lewis acid catalyst. The reaction occurs with Markovnikov regiochemistry, so the OH group adds to the more highly substituted carbon and the H adds to the less highly substituted carbon. The initial product of the reaction is a vinyl alcohol, also called an enol. The enol immediately rearranges to a more stable ketone via tautomerization. Draw curved arrows to show the movement of electrons in this step of the mechanism

See explanation and image attached

Explanation:

According to Markovnikov regiochemistry, the negative part of the addendum is joined to the more substituted carbon atom. The addition of H-OH to alkynes occurs in the presence of mercury(II) sulfate as a Lewis acid catalyst.

So, the -OH group is added to the highly substituted carbon and the H adds to the less highly substituted carbon.

The enol produced is shown in the mechanism attached to this answer. Rearrangement of this enol form due to keto-enol tautomerism yields the ketone as shown.

Image credit: chemistry steps

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;