Calculate the oxidation numbers of the elements in this equation
2 Al2O3 → 4 Al + 3 O2

Explanation:

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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.

Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O )  = 0

2× ( Oxidation number of Al) +3(−2)=0

2× ( oxidation number of Al) +6

∴ Oxidation number of Al =+3

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fe 55.85 g/mol and h2o 18.02 g/mol.