Consider the dehydration of 2-propanol in sulfuric acid: There is a scheme of a reaction where CH3 CH CH3 with an OH group attached to the second carbon atom dehydrated in the presence of H2SO4. Draw the structure for the product of the dehydration of 2-propanol.

CH2=CH-CH3

Explanation:

One of the ways of preparing alkenes is by dehydration of alcohols using sulphuric acid. The sulphuric acid merely acts as a catalyst in the process.

It begins with the protonation of the -OH group. This is followed by loss of water molecule since water is a good leaving group.

Loss of a proton now completes the mechanism and regenerates the acid catalyst.

The mechanism of dehydration of 2-propanol as well as the product formed in the process is shown in the image attached to this answer.

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