In the reaction below, what is the limiting reactant when 1.24 moles NH3 of reacts with 1.79 moles of NO? 4NH_3 + 6NO (right arrow) 5N_2 + 6H_2O

1. NO
2. H_2O
3. NH_3
4. N_2

1. NO .

Explanation:

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In this case, according to the given information, it turns out possible for us to identify the limiting reactant by simply calculating the moles of any product, say N2, via the moles of each reactant and including the corresponding mole ratio (4:5 and 6:5):

Thus, since NO yields the fewest moles of N2 product, we infer it is the limiting reactant.

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6.4 cm (max) - 25 cm (min)

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