per day of a certain industrial waste chemical arrives at a treatment plant settling pond with a volume of . is destroyed by sunlight, and once in the pond it has a half-life of . Calculate the equilibrium concentration of in the pond. Round your answer to significant digits. g

The question is incomplete, the complete question is;

49.9 g per day of a certain industrial waste chemical P arrives at a treatment plant settling pond with a volume of 300 m^3. P is destroyed by sunlight, and once in the pond it has a half-life of 3.4 h. Calculate the equilibrium concentration of P in the pond. Round your answer to 2 significant digits.

0.034 g/m³

Explanation:

From the question, mass of industrial waste = 49.9 g

It takes 24 hours to complete a day.

Mass per hour;

Mass in = (49.9 g / day) * (1 day /24 hr )

= 2.079 g/hr

Mass out = 0

Mass leaving due to sunlight = k CA V

Half life of the industrial waste = 3.4 h

This is a first order reaction;

Hence;

k = ln2/t1/2

Where, t1/2 = half life

k = 0.693 / 3.4 = 0.2038 hr⁻¹

Mass leaving due to sunlight = k CA V

CA = Mass per hr / kV

= 2.079 g/hr / ( 0.2038 hr⁻¹ x 300 m³ )

= 0.034 g/m³

the answer is a

photosynthesis