Consider the following reaction: CrCl3(s) KCl(s) 2H2SO4(l) - KCr(SO4)2(s) 4HCl(g) green white colorless purple colorless solid solid liquid solid gas When the green solid is mixed with the white solid and the colorless liquid is added, the mixture starts to bubble and fume. When all action has stopped, a wet purple solid containing solid white specks remains. Which substance is the limiting reactant

The limiting reactant is CrCl3

Explanation:

In a reaction, the limiting reactant is that reactant which is present in a quantity that is less than the quantity required.

The amount of product formed depends on the concentration of the limiting reactant.

The excess reactant still remains even after the reaction is completed.

Since the purple product still had some white spots, then KCl was definitely in excess.

If that is the case, then CrCl3 is the limiting reactant.

i'm assuming that the correct answer is indeed the first one/ "a"..

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