What fraction of a sample of Cs-137 will remain after 90.6 years?

Dsolubility let me know if you have any other questions for chemistry

Your question is not clear but if you can explain yourself i would be glad to .  just trying to : ))

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj

Just whant to get ponts soory