When heat is applied to 80 grams of CaCO3, it yields 39 grams of CO2. Determine the percentage of the yield.

The percentage yield of is 90.26%.

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

......(1)

Given mass of = 80 g

Molar mass of = 100 g/mol

Plugging values in equation 1:

For the given chemical equation:

By the stoichiometry of the reaction:

If 1 mole of produces 1 mole of

So, 0.8 moles of will produce = of

Molar mass of = 44 g/mol

Plugging values in equation 1:

The percent yield of a reaction is calculated by using an equation:

......(2)

Given values:

Actual value of = 35.2 g

Theoretical value of = 39 g

Plugging values in equation 2:

Hence, the percentage yield of is 90.26%.

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i think? ?

the answer is option a.