At 40 degrees Celsius CH2O2(aq) will decompose according to the following reaction: 2H2O2(aq) 2H2O(l) + O2(g)
The following data were collected for the concentration of H2O2 at various times.
Times(s) [H2O2](M)
0 1.000
2.16x10^4 0.500
4.32x10^4 0.250
a. Calculate the average rate of decomposition of H2O2 between 0 and 2.16 x 10^4 s. Use this rate to calculate the average rate of production of O2(g) over the same time period.
b. What are these rates for the time period 2.16 3 x10^4 s to 4.32 x 10^4 s?

A. Rate of decomposition of H₂O₂ = 2.31 × 10-⁵ M/s

Average rate of production of O₂ = 1.16 × 10-⁵ M/s

B. Rate of decomposition of H₂O₂ = 1.16 × 10-⁵ M/s

Average rate of production of O₂ = 5.8 × 10-⁶ M/s

Explanation:

The rate of a reaction is defined as the number of moles of reactant converted or the product formed per unit time.

Reaction rate = change in the concentration of product or reactant / time taken for the change.

A. i) For the decomposition of H₂O₂, the reaction equation is given below:

2 H₂O₂ (aq) > 2 H₂O (l) + O₂ (g)

a. the average rate of decomposition of H2O2 between 0 and 2.16 x 10^4 s is calculated as follows :

Rate of decomposition of H₂O₂ = change in concentration / change in time

Rate of decomposition of H₂O₂ = (0.500 - 1.000) M / (2.16 × 10⁴ - 0) s = 2.31 × 10-⁵ M/s

ii) The mole ratio of O₂ to H₂O₂ = 1 : 2 = 0.5

Average rate of production of O₂ = 0.5 × rate of decomposition of H₂O₂

Average rate of production of O₂ = 0.5 × 2.31 × 10-⁵ M/s = 1.16 × 10-⁵ M/s

B. The rate of decomposition of H₂O₂ for the time period 2.16 3 x10^4 s to 4.32 x 10^4 s is calculated as follows:

Rate of decomposition of H₂O₂ = change in concentration / change in time

Rate of decomposition of H₂O₂ = (0.250 - 0.500) M / ( 4.32 × 10⁴ - 2.16 × 10⁴) s = 1.16 × 10-⁵ M/s

ii) The mole ratio of O₂ to H₂O₂ = 1 : 2 = 0.5

Average rate of production of O₂ = 0.5 × rate of decomposition of H₂O₂

Average rate of production of O₂ = 0.5 × 1.16 × 10-⁵ M/s = 5.8 × 10-⁶ M/s

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.